Jerseybean
Comments
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Sorry, wasn't thinking straight. Just ignore my idiocy.
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Wouldn't the simplest and most balanced way be just to run 2 x full Howells with 3 board rounds?
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No, I am talking about a 4441 4414 4144 or 1444 Roman 2D
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Would be interested to know the definitive answer as we have 1 or 2 pairs playing a Roman 2D in clubs I direct at but my understanding was (when we had the rule of 25) that the 2D (any 4441) had to have 17hcp but under the new rules has to have 1…
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...or the multiplex 1993 if you don't want to write one. (P13 at T7 shares every round)
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These are all answered in the tables in the master point handbook, In a Teams event, if there are 27 teams then the top 14 would get awards if 1/2 are entitled.
In your pairs event of 11 the Scales clearly state that there are 5 awards if … -
The regulations are based on number of FULL tables rather than number of pairs.
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The handbook table explicitly says 13 awards for a single winner, it is one of the rarer cases where you lose out.
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Alas this looks like a round down as 13 FULL tables.
From the handbook tables
25-26 tables 13 awards if 1/4
19 tables 13 awards if 1/3
13 tables 13 awards if 1/2 -
You have 9 pairs playing all 8 other pairs in 2 board rounds. That is 16 Boards. Why do you want to credit them for 18?
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I play a version of "Benji" with a partner. As we use a compulsory relay it includes a game force in H. Not my preferred methods but if asked my explanation of 2Chas been:-
"19-20 Balanced, 25 -26 Balanced, 8 playing tricks in an unspecif…